Given a string containing just the characters ‘(‘
, ‘)‘
, ‘{‘
, ‘}‘
, ‘[‘
and ‘]‘
, determine if the input string is valid.
The brackets must close in the correct order, "()"
and "()[]{}"
are all valid but "(]"
and "([)]"
are not.
class Solution { public: bool isValid(string s) { stack<char> parenthese; int len = s.length(); for(int i = 0; i < len; i++){ if(s[i] == ‘(‘ || s[i] == ‘[‘ || s[i] == ‘{‘){ parenthese.push(s[i]); } else if(s[i] == ‘)‘){ if(parenthese.empty() || parenthese.top()!=‘(‘) return false; parenthese.pop(); } else if(s[i] == ‘]‘){ if(parenthese.empty() || parenthese.top()!=‘[‘) return false; parenthese.pop(); } else if(s[i] == ‘}‘){ if(parenthese.empty() || parenthese.top()!=‘{‘) return false; parenthese.pop(); } } if(parenthese.empty()) return true; else return false; } };
原文:http://www.cnblogs.com/qionglouyuyu/p/4687344.html