MZL‘s xor
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 546 Accepted Submission(s): 365
Problem Description
MZL loves xor very much.Now he gets an array A.The length of A is n.He wants to know the xor of all (Ai+Aj)(1≤i,j≤n)
The xor of an array B is defined as B1 xor B2...xor Bn
Input
Multiple test cases, the first line contains an integer T(no more than 20), indicating the number of cases.
Each test case contains four integers:n,m,z,l
A1=0,Ai=(Ai?1?m+z) mod l
1≤m,z,l≤5?105,n=5?105
Output
For every test.print the answer.
Sample Input
2
3 5 5 7
6 8 8 9
Sample Output
14
16
#include <stdio.h>
__int64 a[1000000];
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
int n,m,z,l;
a[0]=0;
scanf("%d%d%d%d",&n,&m,&z,&l);
for(int i=1;i<n;i++)
{
a[i]=(a[i-1]*m+z)%l; // 注意溢出
a[0]^=a[i];
}
printf("%I64d\n",a[0]*2);
}
return 0;
}
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HDU 5344
原文：http://blog.csdn.net/a73265/article/details/47312969
