| Time Limit: 20000MS | Memory Limit: 65536K | |
| Total Submissions: 42155 | Accepted: 13855 | |
| Case Time Limit: 2000MS | ||
Description
Input
Output
Sample Input
7 3 1 5 2 6 3 7 4 2 5 3 4 4 1 1 7 3
Sample Output
5 6 3
Hint
Source
Northeastern Europe 2004, Northern Subregion
ac代码
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
int tree[30][100100],sorted[100010],toleft[30][100010];
int cmp(const void *a,const void *b)
{
return *(int *)a-*(int *)b;
}
void build(int l,int r,int dep)
{
if(l==r)
{
return;
}
int mid=(l+r)>>1;
int same=mid-l+1;
int i;
for(i=l;i<=r;i++)
if(tree[dep][i]<sorted[mid])
same--;
int lpos=l;
int rpos=mid+1;
for(i=l;i<=r;i++)
{
if(tree[dep][i]<sorted[mid])
{
tree[dep+1][lpos++]=tree[dep][i];
}
else
if(tree[dep][i]==sorted[mid]&&same>0)
{
tree[dep+1][lpos++]=tree[dep][i];
same--;
}
else
tree[dep+1][rpos++]=tree[dep][i];
toleft[dep][i]=toleft[dep][l-1]+lpos-l;//1 l傻傻分不清楚
}
build(l,mid,dep+1);//又是1 l傻傻分不清楚
build(mid+1,r,dep+1);
}
int query(int L,int R,int l,int r,int dep,int k)
{
if(l==r)
{
return tree[dep][l];
}
int mid=(L+R)>>1;
int cnt=toleft[dep][r]-toleft[dep][l-1];
if(cnt>=k)
{
int newl=L+toleft[dep][l-1]-toleft[dep][L-1];
int newr=newl+cnt-1;
return query(L,mid,newl,newr,dep+1,k);
}
else
{
int newr=r+toleft[dep][R]-toleft[dep][r];
int newl=newr-(r-l-cnt);
return query(mid+1,R,newl,newr,dep+1,k-cnt);
}
}
int main()
{
int n,m;
// while(scanf("%d%d",&n,&m)!=EOF)
// {
int i;
scanf("%d%d",&n,&m);
memset(tree,0,sizeof(tree));
for(i=1;i<=n;i++)
{
scanf("%d",&tree[0][i]);
sorted[i]=tree[0][i];
}
qsort(sorted+1,n,sizeof(sorted[1]),cmp);
build(1,n,0);
while(m--)
{
int a,b,k;
scanf("%d%d%d",&a,&b,&k);
int ans=query(1,n,a,b,0,k);
printf("%d\n",ans);
}
// }
}版权声明:本文为博主原创文章,未经博主允许不得转载。
原文:http://blog.csdn.net/yu_ch_sh/article/details/47320297