https://leetcode.com/problems/length-of-last-word/
题目：
Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
思路：
主要是确定最后一个单词的边界。注意特殊情况。
AC代码：
1 class Solution { 2 public: 3 int lengthOfLastWord(string s) { 4 int begin=-1,end=-1,j,n=s.size(); 5 for(j=n-1;j>=0;j--) 6 if(s[j]!=‘ ‘){ 7 begin=j; 8 break; 9 } 10 if(begin==-1) 11 return 0; 12 for(j=begin;j>=0;j--){ 13 if(s[j]==‘ ‘){ 14 end=j+1; 15 break; 16 } 17 } 18 if(end==-1) 19 end=0; 20 return begin-end+1; 21 } 22 };
Leetcode(58)题解:Length of Last Word
原文：http://www.cnblogs.com/aezero/p/4709149.html