python 按照list中的dic的某key排序

面试题之一。

s=[
{"name":"Axx","score":"90"},
{"name":"Bxx","score":"91"},
{"name":"Cxx","score":"20"},
]

请用一行代码对上述list，按照score排序。

s=[
{"name":"Axx","score":"90"},
{"name":"Bxx","score":"91"},
{"name":"Cxx","score":"20"},
]
print "original s: ",s
new_s = sorted(s,key = lambda e:e.__getitem__('score'))
print "new s: ",new_s

original s:  [{‘score‘: ‘90‘, ‘name‘: ‘Axx‘}, {‘score‘: ‘91‘, ‘name‘: ‘Bxx‘}, {‘score‘: ‘20‘, ‘name‘: ‘Cxx‘}]
new s:  [{‘score‘: ‘20‘, ‘name‘: ‘Cxx‘}, {‘score‘: ‘90‘, ‘name‘: ‘Axx‘}, {‘score‘: ‘91‘, ‘name‘: ‘Bxx‘}]

吐槽：print字典的排序和我s的定义顺序貌似不一样，我定义是name,score，print出来是score再name。貌似也无关紧要，dic本来就无序。

python 按照list中的dic的某key排序

原文：http://blog.csdn.net/emaste_r/article/details/47373011