问题描述
Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest substring is "b", with the length of 1.
解决思路
双指针 + HashSet
前后两个指针，开始时均指向第一个元素，将第一个元素加入HashSet中。
然后移动后指针，只要set中不包含指向元素则移动后指针，不断记录两个指针间的最大长度差（即为不重复字符的字符串）。
时间复杂度和空间复杂度均为O(n).
程序
public class Solution {
public int lengthOfLongestSubstring(String s) {
if (s == null || s.length() == 0) {
return 0;
}
int len = s.length();
int max = 1;
HashSet<Character> set = new HashSet<>();
int low = 0, high = 0;
while (high < len) {
char c = s.charAt(high);
if (!set.contains(c)) {
set.add(c);
++high;
max = Math.max(max, high - low);
continue;
}
char t = s.charAt(low);
set.remove(t);
++low;
}
return max;
}
}
Longest Substring Without Repeating Characters
原文：http://www.cnblogs.com/harrygogo/p/4721044.html