Invert a binary tree.
4 / 2 7 / \ / 1 3 6 9
to
4 / 7 2 / \ / 9 6 3 1
Trivia:
This problem was inspired by this original tweet by Max Howell:
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.
1 /** 2 * Definition for a binary tree node. 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 class Solution { 11 public: 12 TreeNode* invertTree(TreeNode* root) { 13 TreeNode *result=root; 14 15 if(root==NULL) return NULL; 16 invertTreeNode(root); 17 invertTree(root->left); 18 invertTree(root->right); 19 20 return result; 21 22 } 23 24 void invertTreeNode(TreeNode *node) 25 { 26 if(node==NULL) 27 return; 28 TreeNode *temp=node->left; 29 node->left=node->right; 30 node->right=temp; 31 } 32 };
原文:http://www.cnblogs.com/xiaoying1245970347/p/4729975.html