1+2+3+……+n的非循环解法

#include "stdafx.h"
#include "iostream"
using namespace std;

class Temp
{
public:
	Temp()
	{
		++N;
		Sum += N;
	}
	/*
	//在类没有实例化对象之前，如果想使用static数据成员，只能使用static成员函数//
	*/
	static void Reset()
	{
		N = 0;
		Sum = 0;
	}
	static int GetSum()
	{
		return Sum;
	}

private:
	static int N;
	static int Sum;
};
int Temp::Sum = 0;
int Temp::N = 0;


int solution1_Sum(int n)
{
	Temp::Reset();
	Temp*a = new Temp[n];
	delete a;
	a = NULL;
	return Temp::GetSum();
}
int _tmain(int argc, _TCHAR* argv[])
{
	cout<<solution1_Sum(100)<<endl;
	return 0;
}

1+2+3+……+n的非循环解法,布布扣,bubuko.com

1+2+3+……+n的非循环解法

原文：http://blog.csdn.net/gaoxiangky/article/details/22434729