Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 42585 Accepted Submission(s): 18653
2 1 1 2 3 3 3 1 2 5 2 3 5 3 1 2 0 0
3 2
AC-code:
#include<cstdio>
#define max 0x3f3f3f3f
#define min(a,b) (a>b?b:a)
int n,dis[105],cost[105][105];
void dijkstra(int a)
{
int i,vis[105];
for(i=1;i<=n;i++)
{
dis[i]=max;
vis[i]=0;
}
dis[a]=0;
while(1)
{
int v=-1;
for(i=1;i<=n;i++)
if(!vis[i]&&(v==-1||dis[i]<dis[v]))
v=i;
if(v==-1)
break;
vis[v]=1;
for(i=1;i<=n;i++)
dis[i]=min(dis[i],dis[v]+cost[v][i]);
}
}
int main()
{
int m,i,j,a,b,c;
while(scanf("%d%d",&n,&m),n||m)
{
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
cost[i][j]=max;
for(i=1;i<=m;i++)
{
scanf("%d%d%d",&a,&b,&c);
cost[a][b]=cost[b][a]=min(cost[a][b],c);
}
dijkstra(1);
printf("%d\n",dis[n]);
}
return 0;
}
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原文:http://blog.csdn.net/lin14543/article/details/47723125