LeetCode: Add Digits

题目链接：https://leetcode.com/problems/add-digits/

题目：

Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.

For example:

Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.

题意：给定一个非负整数num，将其个位重复相加直到其结果仅有一位为止

题目很简单，直接贴代码吧~

public class Solution {
    public int addDigits(int num) {
        int result = 0;
        int gewei = 0;
        
        if(num/10 == 0)
            return num;
        
        while(num != 0) {
            gewei = num % 10;
            result += gewei;
            num /= 10;
        }
        
        if(result >= 10)
            return addDigits(result);
        else
            return result;
    }
}

LeetCode: Add Digits

原文：http://blog.csdn.net/yangyao_iphone/article/details/47984707