https://leetcode.com/problems/add-two-numbers/
You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
ListNode* res = new ListNode(0);
int tmp = 0,cnt = 0;
ListNode * result = res;
while(l1||l2||cnt){
tmp = cnt;
tmp += (l1?l1->val:0) + (l2?l2->val:0);
cnt = tmp / 10;
tmp %= 10;
if(l1)l1=l1->next;
if(l2)l2=l2->next;
res->val = tmp;
if(l1||l2||cnt){
res->next = new ListNode(0);
res = res->next;
}
}
return result;
}
};
LeetCode 2 Add Two Numbers 模拟,读题 难度:0
原文：http://www.cnblogs.com/xuesu/p/4762610.html