You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { 12 ListNode *root=new ListNode(0); 13 ListNode *curNode,*pNode; 14 curNode=root; 15 int i,j,sum=0,carry=0; 16 while(l1!=NULL||l2!=NULL) 17 { 18 if(l1==NULL) 19 i=0; 20 else 21 i=l1->val; 22 if(l2==NULL) 23 j=0; 24 else 25 j=l2->val; 26 sum=i+j+carry; 27 carry=sum/10; 28 sum%=10; 29 ListNode *pNode=new ListNode(sum); 30 curNode->next=pNode; 31 curNode=pNode; 32 33 if(l1) l1 = l1->next; 34 if(l2) l2 = l2->next; 35 } 36 if(carry>0) 37 { 38 ListNode *pNode=new ListNode(1); 39 curNode->next = pNode; 40 } 41 42 return root->next; 43 } 44 };
原文:http://www.cnblogs.com/hexhxy/p/4789795.html