Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime
complexity. Could you implement it without using extra memory?
public class Solution {
public int singleNumber(int[] A) {
int a
= 0;
for(int i = 0; i < A.length; i++){
a ^=
A[i];
}
return a;
}
}
原文:http://www.cnblogs.com/boole/p/3639253.html