链接:
http://acm.hdu.edu.cn/showproblem.php?pid=5443
Time Limit: 1500/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 738 Accepted Submission(s): 591
#include<iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<queue> #include<vector> #include<cmath> using namespace std; #define N 1110 #define INF 0xffffff #define Lson r<<1 #define Rson r<<1|1 #define Mid a[r].mid() struct node { int L, R, Max; int mid() {return (L+R)/2;} }a[N*4]; int n, m; void BuildTree(int r, int L, int R) { a[r].L = L, a[r].R = R, a[r].Max = 0; if(L==R) { scanf("%d", &a[r].Max); return ; } BuildTree(Lson, L, Mid); BuildTree(Rson, Mid+1, R); a[r].Max = max(a[Lson].Max, a[Rson].Max); } int Query(int r, int L, int R) { if(a[r].L==L && a[r].R==R) { return a[r].Max; } if(R<=Mid) return Query(Lson, L, R); else if(L>Mid) return Query(Rson, L, R); else { int LMax = Query(Lson, L, Mid); int RMax = Query(Rson, Mid+1, R); return max(LMax, RMax); } } int main() { int t; scanf("%d", &t); while(t--) { int i, L, R; scanf("%d", &n); BuildTree(1, 1, n); scanf("%d", &m); for(i=1; i<=m; i++) { scanf("%d%d", &L, &R); printf("%d\n", Query(1, L, R)); } } return 0; }
(线段树 区间查询)The Water Problem -- hdu -- 5443 (2015 ACM/ICPC Asia Regional Changchun Online)
原文:http://www.cnblogs.com/YY56/p/4820865.html