LeetCode -- Reverse Integer

public int Reverse(int x) 
{


var s = x.ToString();
var len = s.Length;
if(len == 1){
return x;
}


var result = string.Empty;
if(s[0] == ‘-‘){
result = "-";
for(var i = 1;i < len; i++){
result += s[len-i];
}
}else{
for(var i = 0;i < len; i++){
result += s[len-i-1];
}
}


var r = 0;
Int32.TryParse(result,out r);
return r;


}

LeetCode -- Reverse Integer

原文：http://blog.csdn.net/lan_liang/article/details/48576053