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[LeetCode 223] Rectangle Area

时间:2015-09-24 07:07:11      阅读:241      评论:0      收藏:0      [点我收藏+]

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

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Assume that the total area is never beyond the maximum possible value of int.


solution:

Math, get total area of two rectangle, minus overlap area.

public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int blx = Math.max(A, E);
        int bly = Math.max(B, F);
        int rtx = Math.min(C, G);
        int rty = Math.min(D, H);
        int res = (C-A) * (D-B) + (G-E) * (H-F);
        if(blx >= rtx || bly >= rty) return res;
        return res - (rtx - blx) * (rty - bly);
    }



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[LeetCode 223] Rectangle Area

原文:http://blog.csdn.net/sbitswc/article/details/48702961

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