Java基础知识强化之IO流笔记02：try...catch的方式处理异常

 1 package com.himi.trycatch;
 2 
 3 public class ExceptionDemo {
 4 
 5     public static void main(String[] args) {
 6         int a = 2;
 7         int b = 0;
 8         try {
 9             System.out.println(a / b);
10         } catch (ArithmeticException ae) {
11             System.out.println("除数不能为0");
12         }
13         System.out.println("over");
14 
15     }
16 
17 }