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__author__ =
‘ledao‘def numOfEqualX(X, n, m=6): if
1 ==
n: if
X >=
1 and X <=m: return
1 else: return
0 sum
=
0 for
k in
range(1, m+1): sum
+=
numOfEqualX(X-k, n-1
) return
sumprint( numOfEqualX(11, 2, 6))print
(numOfEqualX(12, 2, 6))print((numOfEqualX(11, 2) +
numOfEqualX(12, 2) ) /
( 6**2) ) |
原文：http://www.cnblogs.com/ledao/p/3638698.html