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【leetcode】删除单向链表的节点

时间:2015-10-05 18:03:44      阅读:203      评论:0      收藏:0      [点我收藏+]

题目:


Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.


Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    void deleteNode(ListNode* node) {
        
    }
};

好久没做算法题了,随便找了一题leetcode上最easy的题都不会!

看了答案才知道真的很简单啊,然并卵。。。。。。。。

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    void deleteNode(ListNode* node) {
        node->val = node->next->val;
        ListNode* tmp = node->next;
        node->next = tmp->next;
        delete tmp;
    }
};

 

【leetcode】删除单向链表的节点

原文:http://www.cnblogs.com/wenma/p/4855933.html

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