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给一串字符 按奇偶数位输出

时间:2015-10-06 15:16:46      阅读:261      评论:0      收藏:0      [点我收藏+]
 1 #define _CRT_SECURE_NO_WARNINGS
 2 #include<stdio.h>
 3 #include<stdlib.h>
 4 #include<string.h>
 5 
 6 int getStr1Str2(char *source, char *buf1, char *buf2)
 7 {
 8     char *tmpSource = source;
 9     char *tmpBuf1 = buf1;
10     char *tmpBuf2 = buf2;
11 
12     int len = 1;
13 
14     while (*tmpSource!=\0)
15     {
16         if (len % 2)//奇数
17         {
18 
19             *tmpBuf1++ = *tmpSource++;
20             len++;
21         }
22         else
23         {
24             *tmpBuf2++ = *tmpSource++;
25             len++;
26         }
27          
28     }
29     *tmpBuf1 = \0;
30     *tmpBuf2 = \0;
31 }
32 int main()
33 {
34     char *source = "1a2b3d4z";
35     char *buf1 = (char*)malloc(100);
36     char *buf2 = (char*)malloc(100);
37     getStr1Str2(source, buf1, buf2);
38     printf("buf1奇数位:%s\n",buf1);
39     printf("buf2偶数位:%s\n", buf2);
40     system("pause");
41     return 0;
42 }

 

给一串字符 按奇偶数位输出

原文:http://www.cnblogs.com/linst/p/4857092.html

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