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Word Break

时间:2015-10-08 02:09:19      阅读:257      评论:0      收藏:0      [点我收藏+]

Given a string?s?and a dictionary of words?dict, determine if?s?can be segmented into a space-separated sequence of one or more dictionary words.

For example, given
s?=?"leetcode",
dict?=?["leet", "code"].

Return true because?"leetcode"?can be segmented as?"leet code".

?

import java.util.Set;

public class Solution {
    public boolean wordBreak(String s, Set<String> wordDict) {
        boolean[] flag = new boolean[s.length()];
        return solve(s, 0, wordDict, flag);
    }

	private boolean solve(String s, int now, Set<String> wordDict, boolean[] flag) {
		// TODO Auto-generated method stub
		if (now >= s.length()) {
			return true;
		}
		if (flag[now]) {
			return false;
		}
		flag[now] = true;
		for (int i = now; i < s.length(); i++) {
			if (wordDict.contains(new String(s.getBytes(), now, i-now+1)) && solve(s, i+1, wordDict, flag)) {
				return true;
			}
		}
		return false;
	}
}

?

Word Break

原文:http://hcx2013.iteye.com/blog/2247393

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