Description：
Given an array of non-negative integers, you are initially positioned at the first index of the array.
Each element in the array represents your maximum jump length at that position.
Determine if you are able to reach the last index.
For example:
A = [2,3,1,1,4], return true.
A = [3,2,1,0,4], return false.
贪心，每次取最大step看是否能够到达最后的索引。
public class Solution { public boolean canJump(int[] nums) { if(nums.length == 0 || nums.length == 1) return true; int maxStep = nums[0]; for(int i=0; i<nums.length; i++) { if(maxStep == 0) { return false; } maxStep = Math.max(maxStep-1, nums[i]); if(maxStep+i >= nums.length-1) { return true; } } return true; } }
原文：http://www.cnblogs.com/wxisme/p/4879033.html