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LeetCode OJ:Delete Node in a Linked List(链表节点删除)

时间:2015-10-18 11:16:57      阅读:278      评论:0      收藏:0      [点我收藏+]

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

 1 /**
 2  * Definition for singly-linked list.
 3  * struct ListNode {
 4  *     int val;
 5  *     ListNode *next;
 6  *     ListNode(int x) : val(x), next(NULL) {}
 7  * };
 8  */
 9 
10 class Solution {
11 public:
12     void deleteNode(ListNode* node) {
13         if(node == NULL) return;
14         node->val = node->next->val;
15         node->next = node->next->next;
16     }
17 };

 

LeetCode OJ:Delete Node in a Linked List(链表节点删除)

原文:http://www.cnblogs.com/-wang-cheng/p/4889053.html

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