Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 60672 Accepted Submission(s): 26288
1 #include<stdio.h> 2 int main (void) 3 { 4 int n, m, i, j, sum, count; 5 6 while(scanf("%d %d", &n, &m) == 2){ 7 i = 0; 8 j = sum = 0; 9 for(i = 1; i <= n; i++){ 10 sum += 2*i; 11 if(i%m == 0){ 12 printf("%d", sum/m); 13 if(i != n) 14 putchar(‘ ‘); 15 j += sum; 16 sum -= sum; 17 count = i; 18 } 19 } 20 if(n%m != 0) 21 printf("%d\n", sum/(n-count)); 22 else 23 putchar(‘\n‘); 24 } 25 return 0; 26 }
原文:http://www.cnblogs.com/clairvoyant/p/4889897.html