Given an array of strings, return all groups of strings that are anagrams.
Note: All inputs will be in lower-case.
Solution: Sort the string to see if they‘re anagrams.
1 class Solution {
2 public:
3 vector<string> anagrams(vector<string> &strs) {
4 map<string,vector<int> > hashmap; // apply hashmap (BST)
5 for(int i = 0; i < strs.size(); i++) {
6 string s = strs[i];
7 sort(s.begin(), s.end());
8 hashmap[s].push_back(i);
9 }
10
11 vector<string> res;
12 for(map<string,vector<int> >::iterator it = hashmap.begin(); it != hashmap.end(); it++) {
13 vector<int>& tmp = it->second;
14 for(int i = 0; i < tmp.size(); i++) {
15 if(tmp.size() > 1) {
16 res.push_back(strs[tmp[i]]);
17 }
18 }
19 }
20 return res;
21 }
22 };
原文:http://www.cnblogs.com/zhengjiankang/p/3646362.html