首页 > 其他 > 详细

dataStructure@ Find if there is a path between two vertices in a directed graph

时间:2015-10-23 20:06:13      阅读:364      评论:0      收藏:0      [点我收藏+]

Given a Directed Graph and two vertices in it, check whether there is a path from the first given vertex to second. For example, in the following graph, there is a path from vertex 1 to 3. As another example, there is no path from 3 to 0.

技术分享

We can either use Breadth First Search (BFS) or Depth First Search (DFS) to find path between two vertices. Take the first vertex as source in BFS (or DFS), follow the standard BFS (or DFS). If we see the second vertex in our traversal, then return true. Else return false.

Following is C++ code that uses BFS for finding reachability of second vertex from first vertex.

技术分享
 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 #include<limits>
 5 #include<vector>
 6 using namespace std;
 7 const int maxn = 4;
 8 struct edge{
 9     int to, cost;
10     edge(int t){
11         this->to = t; this->cost = 0;
12     }
13 };
14 void addEdge(vector<edge> &edgelist, vector<vector<int> > &G, int from, int to){
15     edgelist.push_back(edge(to));
16     G[from].push_back(edgelist.size()-1);
17 }
18 void addDoubleEdge(vector<edge> &edgelist, vector<vector<int> > &G, int from, int to){
19     addEdge(edgelist,G,from,to);
20     addEdge(edgelist,G,to,from);
21 }
22 bool isCyclic(vector<edge> edgelist, vector<vector<int> > G,vector<bool> vis, vector<bool> RecStack, int v){
23     for(int i=0;i<G[v].size();++i){
24         edge e = edgelist[G[v][i]];
25         if(RecStack[e.to]) return true;
26         if(!vis[e.to]){
27             vis[e.to] = true; RecStack[e.to] = true;
28             if(isCyclic(edgelist,G,vis,RecStack,e.to)) return true;
29             RecStack[e.to] = false;
30         }
31     }
32     return false;
33 }
34 void isCyclicUtil(vector<edge> edgelist, vector<vector<int> > G){// find all cycles.
35     vector<bool> vis(G.size());
36     vector<bool> RecStack(G.size());
37     for(int i=0;i<vis.size();++i) vis[i]=false;
38     for(int i=0;i<RecStack.size();++i) RecStack[i]=false;
39     
40     for(int i=0;i<G.size();++i){
41         if(!vis[i]){
42             vis[i] = true; RecStack[i] = true;
43             if(isCyclic(edgelist,G,vis,RecStack,i)){
44                 cout<<i<<" starts a cycle"<<endl; 
45             }
46             RecStack[i] = false;
47         }
48     }
49 }
50 bool dfs(vector<edge> edgelist, vector<vector<int> > G, vector<bool> vis, int from, int to){
51     if(from == to) return true;
52     for(int i=0;i<G[from].size();++i){
53         edge e = edgelist[G[from][i]];
54         if(e.to == to) return true;
55         if(!vis[e.to]){
56             vis[e.to] = true;
57             if(dfs(edgelist, G, vis, e.to, to)) return true;
58         }
59     }
60     return false;
61 }
62 void isReachable(vector<edge> edgelist, vector<vector<int> > G, int from, int to){
63     vector<bool> vis(G.size());
64     for(int i=0;i<vis.size();++i) vis[i] = false;
65     vis[from] = true;
66     if(dfs(edgelist, G, vis, from, to)) cout<<from<<" and "<<to<<" are reachable to each other"<<endl;
67     else cout<<from<<" and "<<to<<" are not reachable to each other"<<endl;
68 }
69 void buildMap(vector<edge> &edgelist, vector<vector<int> > &G){
70     addEdge(edgelist,G,0,1);
71     addEdge(edgelist,G,0,2);
72     addEdge(edgelist,G,2,0);
73     addEdge(edgelist,G,1,2);
74     addEdge(edgelist,G,2,3);
75     addEdge(edgelist,G,3,3);
76 }
77 int main(){
78     vector<edge> edgelist;
79     vector<vector<int> > G(maxn);
80     
81     buildMap(edgelist,G);
82     
83     isCyclicUtil(edgelist, G);
84     
85     isReachable(edgelist, G, 1, 1);
86     
87     return 0;
88 }
View Code

 

dataStructure@ Find if there is a path between two vertices in a directed graph

原文:http://www.cnblogs.com/fu11211129/p/4905497.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!