Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
For example,
If n = 4 and k = 2, a solution is:
[ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ]
组合问题,老思路---递归加循环,这个是组合里面比較简单的。
class Solution {
public:
vector<vector<int> > combine(int n, int k) {
vector<vector<int> > ret;
helper(k, 1, n, vector<int>(), ret);
return ret;
}
void helper(int k, int start, int n, vector<int> part, vector<vector<int> > &ret){
if(k==part.size()){
ret.push_back(part);
return;
}
for(int i=start; i<=n; ++i){
part.push_back(i);
helper(k, i+1, n, part, ret);
part.pop_back();
}
}
};版权声明:本文博主原创文章。博客,未经同意不得转载。
原文:http://www.cnblogs.com/bhlsheji/p/4909162.html