Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 28818 Accepted Submission(s): 17516
1 #include<stdio.h> 2 #include<string.h> 3 int main (void) 4 { 5 char a[400], temp[200]; 6 int i, j, k, n, len; 7 while(scanf("%d\n", &n) == 1){ 8 for(i = 0; i < n; i++){ 9 gets(a); 10 int count = 0; 11 for(j = 0, k = strlen(a)-1; j < strlen(a)/2; j++, k--) 12 if(a[j] != a[k]) 13 count = 1; 14 if(count == 1) 15 printf("no\n"); 16 else 17 printf("yes\n"); 18 } 19 } 20 return 0; 21 }
HDU 2009 Palindromes _easy version
原文:http://www.cnblogs.com/clairvoyant/p/4910056.html