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Course Schedule

时间:2015-10-27 02:11:49      阅读:250      评论:0      收藏:0      [点我收藏+]

here are a total of?n?courses you have to take, labeled from?0?to?n - 1.

Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair:?[0,1]

Given the total number of courses and a list of prerequisite?pairs, is it possible for you to finish all courses?

For example:

2, [[1,0]]

There are a total of 2 courses to take. To take course 1 you should have finished course 0. So it is possible.

2, [[1,0],[0,1]]

There are a total of 2 courses to take. To take course 1 you should have finished course 0, and to take course 0 you should also have finished course 1. So it is impossible.

?

public class Solution {
    public boolean canFinish(int numCourses, int[][] prerequisites) {
        ArrayList<Set<Integer>> arrayList = new ArrayList<>();
        for (int i = 0; i < numCourses; i++) {
        	arrayList.add(new HashSet<Integer>());
		}
        for (int i = 0; i < prerequisites.length; i++) {
        	arrayList.get(prerequisites[i][1]).add(prerequisites[i][0]);
		}
        int[] preNum = new int[numCourses];
        for (int i = 0; i < numCourses; i++) {
        	Set<Integer> set = arrayList.get(i);
        	Iterator<Integer> iterator = set.iterator();
        	while (iterator.hasNext()) {
        		preNum[iterator.next()]++;
        	}
		}
        for (int i = 0; i < numCourses; i++) {
			int j = 0;
			for (; j < numCourses; j++) {
				if (preNum[j] == 0) {
					break;
				}
			}
			if (j == numCourses) {
				return false;
			}
			preNum[j] = -1;
			Set<Integer> set = arrayList.get(j);
			Iterator<Integer> iterator = set.iterator();
			while (iterator.hasNext()) {
        		preNum[iterator.next()]--;
        	}
		}
        return true;
    }
}

?

Course Schedule

原文:http://hcx2013.iteye.com/blog/2252095

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