To prepare for the English exam Little Ho collected many digital reading materials. Unfortunately the materials are messed up by a malware.
It is known that the original text contains only English letters (a-zA-Z), spaces, commas, periods and newlines, conforming to the following format:
1. Each sentence contains at least one word, begins with a letter and ends with a period.
2. In a sentence the only capitalized letter is the first letter.
3. In a sentence the words are separated by a single space or a comma and a space.
4. The sentences are separated by a single space or a single newline.
It is also known the malware changes the text in the following ways:
1. Changing the cases of letters.
2. Adding spaces between words and punctuations.
Given the messed text, can you help Little Ho restore the original text?
A string containing no more than 8192 English letters (a-zA-Z), spaces, commas, periods and newlines which is the messed text.
The original text.
Sample Input
my Name is Little Hi. His name IS Little ho , We are friends.
Sample Output
My name is little hi. His name is little ho, we are friends.
Solution:
1 #include <cstdio> 2 #include <cstring> 3 #define MAXN 10000 4 5 char toUpper(char c) { 6 if (c >= ‘A‘ && c <= ‘Z‘) return c; 7 else return ‘A‘ + (c - ‘a‘); 8 } 9 10 char toLower(char c) { 11 if (c >= ‘a‘ && c <= ‘z‘) return c; 12 else return ‘a‘ + (c - ‘A‘); 13 } 14 15 int main() { 16 char buf[MAXN]; 17 char text[MAXN]; 18 while (fgets(buf, MAXN, stdin)) { 19 //printf("%s\n", buf); 20 int len = strlen(buf); 21 int idx = -1; 22 int k = 0; 23 int flag = true; 24 for (int i = 0; i < len; ++i) { 25 26 if ((buf[i] >= ‘a‘ && buf[i] <= ‘z‘) || buf[i] >= ‘A‘ && buf[i] <= ‘Z‘) { 27 if (idx >= 0) { 28 k = idx + 1; 29 idx = -1; 30 } 31 if (flag) { 32 text[k++] = toUpper(buf[i]); 33 flag = false; 34 } 35 else 36 text[k++] = toLower(buf[i]); 37 } 38 else if (buf[i] == ‘ ‘) { 39 if (idx < 0) { 40 idx = k; 41 } 42 text[k++] = buf[i]; 43 } 44 else if (buf[i] == ‘,‘) { 45 if (idx >= 0) { 46 k = idx; 47 idx = -1; 48 } 49 text[k++] = buf[i]; 50 } 51 else if (buf[i] == ‘.‘) { 52 if (idx >= 0) { 53 k = idx; 54 idx = -1; 55 } 56 text[k++] = buf[i]; 57 flag = true; 58 } 59 else text[k++] = buf[i]; 60 61 } 62 text[k] = ‘\0‘; 63 printf("%s", text); 64 } 65 66 }
hihoCoder #1197 Give My Text Back
原文：http://www.cnblogs.com/liew/p/4916977.html