?(>_o)! is a pseudo-object-oriented programming language. It implements the following commands:
| Command | Description |
|---|---|
| ? | Check whether the character ‘?‘ is in the program‘s source code. If ‘?‘ does not exist in the program‘s source, the hardware will catch fire or explode. |
| ( | It tries to match ‘)‘, although mismatch of brackets does not matter at all. |
| > | Increase the internal accumulator. |
| _ | Print the program‘s source code. |
| o | Instantiate an object of a new sub class of the generic super class. Due to the best principles of object hiding, this object cannot be accessed in any way. |
| ) | Just matches ‘(‘. It‘s for patient with obsessive-compulsive disorder. However, mismatch of brackets does not matter at all. |
| ! | Print "Hello, world!". |
| Other characters | Be treated as comments rather than instruction. |
However, it‘s only another joke programming language. There is even no way to access the accumulator. But it‘s one of easiest to finish a "Hello world" program or a quine program. A quine is a computer program which takes no input and produces a copy of its own source code as its only output. Your task is to judge whether a ?(>_o)! program is a quine.
There are multiple test cases. The first line of input is an integer T indicates the number of test cases. For each test case:
There is one line of string represents the source code of a ?(>_o)! program. The program contains no more than 256 characters. The ASCII value of each character is within [32, 126].
For each test case, output "Yes" if it is a quine. Otherwise, output "No".
4 Hello, world! source_code source__code ?(>_o)!
Yes Yes No No
#include<stdio.h> #include<string.h> int main() { int xhx,gth,t,i; char str[1000],holl[100]="Hello, world!"; scanf("%d",&t);getchar(); while(t--) { gets(str); xhx=gth=0; int len=strlen(str); for( i=0;i<len;i++) if(str[i]==‘_‘) xhx++; else if(str[i]==‘!‘) gth++; if(xhx>1) { printf("No\n");continue; } if(xhx==1&>h==0) { printf("Yes\n");continue; } char ss[10000]; int slen=0; while(gth--) { for(i=0;i<13;i++) ss[slen++]=holl[i]; } ss[slen]=‘\0‘; printf("%s\n",(strcmp(ss,str))==0?"Yes":"No"); } }
ZOJ3775 ?(>_o)!,布布扣,bubuko.com
原文：http://blog.csdn.net/u010372095/article/details/23098589