SQL Server 求结果

;with cte as (        

　　select  CONVERT(DATE, DATEADD(DAY, -9, GETDATE())) as paytime        

　　union all        

　　select dateadd(day,1,paytime) from cte where paytime<GETDATE()

)

select * from cte a

-----------猜猜结果是什么，下面的

paytime
2015-10-31
2015-11-01
2015-11-02
2015-11-03
2015-11-04
2015-11-05
2015-11-06
2015-11-07
2015-11-08
2015-11-09
2015-11-10

SQL Server 求结果

原文：http://www.cnblogs.com/theonewu/p/4948933.html