首页 > 其他 > 详细

[LeetCode] Valid Anagram

时间:2015-11-09 12:48:23      阅读:236      评论:0      收藏:0      [点我收藏+]

Given two strings s and t, write a function to determine if t is an anagram of s.

For example,
s = “anagram”, t = “nagaram”, return true.
s = “rat”, t = “car”, return false.

Note:
You may assume the string contains only lowercase alphabets.

Follow up:
What if the inputs contain unicode characters? How would you adapt your solution to such case?

解题思路

先排序,再比较是否相等。

实现代码

Java:

// Runtime: 8 ms
public class Solution {
    public boolean isAnagram(String s, String t) {
        char s1[] = s.toCharArray();
        char t1[] = t.toCharArray();
        Arrays.sort(s1);
        Arrays.sort(t1);

        return String.valueOf(s1).equals(String.valueOf(t1));
    }
}

版权声明:本文为博主原创文章,未经博主允许不得转载。

[LeetCode] Valid Anagram

原文:http://blog.csdn.net/foreverling/article/details/49736185

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!