python判断成绩给等级

输入一个测验成绩评定A-F

A:90-100

B:80-89

C:70-79

D:60-69

F:<60

#!/usr/bin/env python 
score = int(raw_input(‘Please enter a score:‘))
def print_score(g):
        print "your score is %s " % g
if 90 < score <= 100:
        print_score(‘A‘)
elif score > 80:
        print_score(‘B‘)
elif score > 70:
        print_score(‘C‘)
elif score > 60:
        print_score(‘D‘)
else:
        print_score(‘F‘)

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python判断成绩给等级

原文：http://hongtengfei.blog.51cto.com/9881650/1711990