首页 > 其他 > 详细

LeetCode -- Sum Root to Leaf Numbers

时间:2015-11-17 13:02:44      阅读:269      评论:0      收藏:0      [点我收藏+]
题目描述:


Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.


An example is the root-to-leaf path 1->2->3 which represents the number 123.


Find the total sum of all root-to-leaf numbers.


For example,


    1
   / \
  2   3
The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.


Return the sum = 12 + 13 = 25.


思路:
DFS问题,即从根节点出发进入统计(存为string s),如果左节点不为空,进入左子树统计;如果右子树不为空进入右子树统计。如果是叶子节点,记录状态放入总结果(List<string> result)。
遍历完之后,再遍历一遍result转为整形累加计算结果即可。


实现代码:


/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     public int val;
 *     public TreeNode left;
 *     public TreeNode right;
 *     public TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public int SumNumbers(TreeNode root) 
    {
        if(root == null){
    		return 0;
    	}
         var ret = new List<string>();
         Sum(root, "",ref ret);
         
         var s = 0;
         for(var i = 0;i < ret.Count; i++){
         	 s += int.Parse(ret[i]);
         }
         
         return s;
    }


private void Sum(TreeNode root, string s,ref List<string> result)
{
	if(root.left == null && root.right == null){
		result.Add(s + root.val);
		return;
	}
	
	if(root.left != null){
		Sum(root.left, s + root.val, ref result);
	}
	if(root.right != null){
		Sum(root.right, s + root.val, ref result);
	}
}
}


版权声明:本文为博主原创文章,未经博主允许不得转载。

LeetCode -- Sum Root to Leaf Numbers

原文:http://blog.csdn.net/lan_liang/article/details/49885323

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!