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给定一个二叉树,寻找值最大的路径。
这个路径可以从这个树上面的任意一个节点开始,然后在任意一个节点结束。
例如:
给定下面的二叉树,
1 / 2 3
返回 6
.
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Given a binary tree, find the maximum path sum.
The path may start and end at any node in the tree.
For
example:
Given the below binary tree,
1 / 2 3
Return 6
.
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test.cpp:
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#include <iostream> #include <cstdio> #include <stack> #include <vector> #include "BinaryTree.h" using namespace std; /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ int max_sum; int dfs(const TreeNode *root) { if(root == NULL) { return 0; } int l = dfs(root->left); int r = dfs(root->right); int sum = root->val; if(l > 0) { sum += l; } if(r > 0) { sum += r; } max_sum = max(max_sum, sum); return max(r, l) > 0 ? max(r, l) + root->val : root->val; } int maxPathSum(TreeNode *root) { max_sum = -0xffff; dfs(root); return max_sum; } // 树中结点含有分叉, // 8 // / \ // 6 1 // / \ // 9 2 // / \ // 4 7 int main() { TreeNode *pNodeA1 = CreateBinaryTreeNode(8); TreeNode *pNodeA2 = CreateBinaryTreeNode(6); TreeNode *pNodeA3 = CreateBinaryTreeNode(1); TreeNode *pNodeA4 = CreateBinaryTreeNode(9); TreeNode *pNodeA5 = CreateBinaryTreeNode(2); TreeNode *pNodeA6 = CreateBinaryTreeNode(4); TreeNode *pNodeA7 = CreateBinaryTreeNode(7); ConnectTreeNodes(pNodeA1, pNodeA2, pNodeA3); ConnectTreeNodes(pNodeA2, pNodeA4, pNodeA5); ConnectTreeNodes(pNodeA5, pNodeA6, pNodeA7); PrintTree(pNodeA1); cout << maxPathSum(pNodeA1) << endl; DestroyTree(pNodeA1); return 0; } |
结果输出:
24
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 |
#ifndef _BINARY_TREE_H_ #define _BINARY_TREE_H_ struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) {} }; TreeNode *CreateBinaryTreeNode(int value); void ConnectTreeNodes(TreeNode *pParent, TreeNode *pLeft, TreeNode *pRight); void PrintTreeNode(TreeNode *pNode); void PrintTree(TreeNode *pRoot); void DestroyTree(TreeNode *pRoot); #endif /*_BINARY_TREE_H_*/ |
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#include <iostream> #include <cstdio> #include "BinaryTree.h" using namespace std; /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ //创建结点 TreeNode *CreateBinaryTreeNode(int value) { TreeNode *pNode = new TreeNode(value); return pNode; } //连接结点 void ConnectTreeNodes(TreeNode *pParent, TreeNode *pLeft, TreeNode *pRight) { if(pParent != NULL) { pParent->left = pLeft; pParent->right = pRight; } } //打印节点内容以及左右子结点内容 void PrintTreeNode(TreeNode *pNode) { if(pNode != NULL) { printf("value of this node is: %d\n", pNode->val); if(pNode->left != NULL) printf("value of its left child is: %d.\n", pNode->left->val); else printf("left child is null.\n"); if(pNode->right != NULL) printf("value of its right child is: %d.\n", pNode->right->val); else printf("right child is null.\n"); } else { printf("this node is null.\n"); } printf("\n"); } //前序遍历递归方法打印结点内容 void PrintTree(TreeNode *pRoot) { PrintTreeNode(pRoot); if(pRoot != NULL) { if(pRoot->left != NULL) PrintTree(pRoot->left); if(pRoot->right != NULL) PrintTree(pRoot->right); } } void DestroyTree(TreeNode *pRoot) { if(pRoot != NULL) { TreeNode *pLeft = pRoot->left; TreeNode *pRight = pRoot->right; delete pRoot; pRoot = NULL; DestroyTree(pLeft); DestroyTree(pRight); } } |
【二叉树的递归】05二叉树中找任意起点和终点使他们的路径和最大【Binary Tree Maximum Path Sum】,布布扣,bubuko.com
【二叉树的递归】05二叉树中找任意起点和终点使他们的路径和最大【Binary Tree Maximum Path Sum】
原文:http://www.cnblogs.com/codemylife/p/3652394.html