思路:利用位运算保存每个通道的放置方法,然后去深搜,要加剪枝。详细见代码
代码:
#include <stdio.h> #include <string.h> #define min(a,b) ((a)<(b)?(a):(b)) #define max(a,b) ((a)>(b)?(a):(b)) const int N = 35; int n, p[5], ans, w[N], wn; char str[N]; bool judge(int s0, int s1, int s2, int s3, int s4) { return ((s0&p[0]) == 0 && (s1&p[1]) == 0 && (s2&p[2]) == 0 && (s3&p[3]) == 0 && (s4&p[4]) == 0); } void init() { ans = 10 * n; wn = 0; for (int i = 0; i < 5; i++) { p[i] = 0; scanf("%s", str); for (int j = n - 1; j >= 0; j--) { p[i] = p[i] * 2 + (str[j] == ‘X‘); } } int s0 = p[0], s1 = p[1], s2 = p[2], s3 = p[3], s4 = p[4]; for (int k = 0; k <= n; k++) { if (judge((s0>>k), (s1>>k), (s2>>k), (s3>>k), (s4>>k))) { w[wn++] = k;//剪枝,开w数组把不能放的位置剔除掉 } } } void dfs(int s0, int s1, int s2, int s3, int s4, int d, int len) { if (len + w[0] * (10 - d) > ans) return;//关键剪枝 if (d == 10) { ans = min(ans, len); return; } for (int i = 0; i < wn; i++) { int ss0 = (s0>>w[i]), ss1 = (s1>>w[i]), ss2 = (s2>>w[i]), ss3 = (s3>>w[i]), ss4 = (s4>>w[i]); if (judge(ss0, ss1, ss2, ss3, ss4)) { dfs(ss0^p[0], ss1^p[1], ss2^p[2], ss3^p[3], ss4^p[4], d + 1, len + w[i]); } } } int main() { while (~scanf("%d", &n) && n) { init(); dfs(p[0], p[1], p[2], p[3], p[4], 1, n); printf("%d\n", ans); } return 0; }
UVA 690 Pipeline Scheduling (搜索+位运算+剪枝),布布扣,bubuko.com
UVA 690 Pipeline Scheduling (搜索+位运算+剪枝)
原文:http://blog.csdn.net/accelerator_/article/details/23189209