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LeetCode -- Search a 2D Matrix II

时间:2015-11-21 11:53:31      阅读:210      评论:0      收藏:0      [点我收藏+]
题目描述:
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:


Integers in each row are sorted in ascending from left to right.
Integers in each column are sorted in ascending from top to bottom.
For example,


Consider the following matrix:


[
  [1,   4,  7, 11, 15],
  [2,   5,  8, 12, 19],
  [3,   6,  9, 16, 22],
  [10, 13, 14, 17, 24],
  [18, 21, 23, 26, 30]
]
Given target = 5, return true.


Given target = 20, return false.


本题看起来是Search a 2D Matrix的扩展问题,其实和第一题的思路完全不一样。比较精简的思路是:
1.从左下开始找,如果matrix[r,c](r为行,c为列) < target,c++;否则r--。
2.直到r或c越界为止。




实现代码:


public class Solution {
    public bool SearchMatrix(int[,] matrix, int target) 
    {
        var rowLen = matrix.GetLength(0);
        var colLen = matrix.GetLength(1);
        
        var row = rowLen - 1;
        var col = 0;
        
        while(col <= colLen - 1 && row >= 0){
            if(matrix[row,col] == target){
                return true;
            }
            else if(matrix[row,col] < target){
                col ++;
            }
            else{
                row --;
            }
        }
        return false;
    }


}


LeetCode -- Search a 2D Matrix II

原文:http://blog.csdn.net/lan_liang/article/details/49962513

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