Given an array of n integers where n > 1, nums
, return an array output
such that output[i]
is equal to the product of all the elements of nums
except nums[i]
.
Solve it without division and in O(n).
For example, given [1,2,3,4]
, return [24,12,8,6]
.
Follow up:
Could you solve it with constant space complexity? (Note: The output array does not count as extra space for the purpose of space complexity analysis.)
class Solution { public: vector<int> productExceptSelf(vector<int>& nums) { int numsSize = nums.size(); vector<int> res(numsSize,1); for(int i=1;i<numsSize;i++){ res[i] = nums[i-1]*res[i-1]; } int tmp = 1; for(int i=numsSize-1;i>=0;i--){ res[i] = res[i]*tmp; tmp *= nums[i]; } return res; } };
原文:http://www.cnblogs.com/zengzy/p/5003043.html