http://www.itint5.com/oj/#39
最大子矩阵和,复杂度O(n^3)。利用了最大子段和的方法。
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int
maxRectSum(vector<vector< int > > &matrix) { int
n = matrix.size(); if
(n == 0) return
0; int
m = matrix[0].size(); if
(m == 0) return
0; int
max = 0; for
( int
i = 0; i < m; i++) { vector< int > vec(n); for
( int
j = i; j < m; j++) { for
( int
k = 0; k < n; k++) { vec[k] += matrix[k][j]; } // vec[k]: sum of row k, from i to j int
sum = 0; for
( int
k = 0; k < n; k++) { if
(sum < 0) sum = 0; sum += vec[k]; if
(sum > max) max = sum; } } } return
max; } |
原文:http://www.cnblogs.com/lautsie/p/3529531.html