Reverse digits of an integer. Returns 0 when the reversed integer overflows (signed 32-bit integer).
Given x = 123, return 321
Given x = -123, return -321
\\\The length of Int data is from -2^31 to 2^31-1; [-2^31 , 2^31 -1] 即 [-2147483648，2147483647]
\\\In Java, using Integer.MAX_VALUE and Integer.MIN_VALUE to record the maximum length and minimum length of int.
\\\In C#, using int.MaxValue and int.MinValue
\\\ use a long type to record result, then compare it to the max or min value, if it exceed, return 0;
public class Solution { /** * @param n the integer to be reversed * @return the reversed integer */ public int reverseInteger(int n) { // Write your code here long res=0; while(n!=0) { int digit=n%10; res=res*10+digit; if(res>Integer.MAX_VALUE || res<Integer.MIN_VALUE) { return 0; } n=n/10; } return (int)res; } }
[lintcode easy]Reverse Integer
原文：http://www.cnblogs.com/kittyamin/p/5008987.html