C++继承中构造函数和析构函数的调用顺序

class Fish:public Animal
{
public:
Fish()
{
cout<<"this is Fish"<<endl;
}
~Fish()
{
cout<<"this is free Fish"<<endl;
}
};

C++继承中父类的构造函数先于子类的构造函数调用；

子类的析构函数的调用顺序先于父类的析构函数调用；

class Animal
{
public:
Animal()
{
cout<<"this is animal"<<endl;
}
~Animal()
{
cout<<"this is free animal"<<endl;
}
};

void main()

{

Fish fish;

}

如果父类中的构造函数含有两个参数，则子类中声明构造函数需要注意

如：

Animal中的构造函数是

Animal(int i,int j)

{}

则子类的构造函数：

Fish():Animal(100,200)

{}

上面两段代码先后顺序颠倒了............................................................................................

                                                                                                                                                                                                                                 ————郭仔

C++继承中构造函数和析构函数的调用顺序,布布扣,bubuko.com

C++继承中构造函数和析构函数的调用顺序

原文：http://blog.csdn.net/guoxianzhuang/article/details/23271961