首页 > 其他 > 详细

[LeetCode]Flatten Binary Tree to Linked List

时间:2015-12-05 14:20:33      阅读:106      评论:0      收藏:0      [点我收藏+]

题目描述:(链)

Given a binary tree, flatten it to a linked list in-place.

For example,
Given

         1
        /        2   5
      / \        3   4   6

 

The flattened tree should look like:

   1
         2
             3
                 4
                     5
                         6

解题思路:
 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     void flatten(TreeNode* root) {
13         if (root == nullptr) return;
14         
15         stack<TreeNode *> cache;
16         cache.push(root);
17         while (!cache.empty()) {
18             auto p = cache.top();
19             cache.pop();
20             
21             if (p->right) {
22                 cache.push(p->right);
23             }
24             
25             if (p->left) {
26                 cache.push(p->left);
27             }
28             
29             p->left = nullptr;
30             if (!cache.empty()) {
31                 p->right = cache.top();
32             }
33             
34         }
35         
36     }
37 };

 

 

[LeetCode]Flatten Binary Tree to Linked List

原文:http://www.cnblogs.com/skycore/p/5021417.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!