#include <stdio.h>
#include <stdlib.h>
int main()
{
int sign = 1;
double deno = 2.0;
double sum = 1.0;
double result = 0;
while (deno <= 100)
{
sign = (-1)*sign;
result = sign / deno;
sum = sum + result;
deno = deno + 1;
}
printf("%f\n", sum);
system("pause");
return 0;
}计算1/1-1/2+1/3-1/4+1/5 …… + 1/99 - 1/100 的值C语言代码
原文：http://10919090.blog.51cto.com/10909090/1719851