【python】函数名存在变量中

LOGIN = ‘xxxx‘
PASSWD = "xxx"
URL = ‘xxxxx‘

def handler_version(url):
    return url

def request_version(url):
    return req

for funcType in (‘handler‘, ‘request‘):
    print ‘*** Using %s:‘ % funcType.lower()
    #a=‘%s_version‘%funcType
    url = eval(‘%s_version‘%funcType)(URL)###wval把string变量转换成相应函数
    #url = a(URL)
    print url
    f = urllib2.urlopen(url)
    print f.readline()
    f.close()