今天发现一个蛋疼的问题，服务端返回的urlString里面有时含有中文,使用
[NSURL URLWithString:urlString]生成URL对象时,iOS客户端不能正确进行网络请求,网上找到的URLEncode方法又不能完全解决问题.
方法1:
NSString* encodedString = [urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
方法2:
NSString * encodedString = (NSString *)CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,(CFStringRef)urlString,NULL,NULL,kCFStringEncodingUTF8);
这两种方法当urlString里含有中文时URL编码是正确的,但是如果其中含有已转义的%等符号时,又会再次转义而导致错误.
查看方法2参数说明:
CFStringRef CFURLCreateStringByAddingPercentEscapes(CFAllocatorRef allocator, CFStringRef originalString, CFStringRef charactersToLeaveUnescaped, CFStringRef legalURLCharactersToBeEscaped, CFStringEncoding encoding);
因此做出修改,写出方法:
NSString *encodedString = (NSString *) CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault, (CFStringRef)urlString, (CFStringRef)@"!$&‘()*+,-./:;=?@_~%#[]", NULL, kCFStringEncodingUTF8);
如果在所有的类里都要用到这个方法,可以写成category,然后在头文件import "NSString+URL.h" 即可调用.
@interface NSString (URL) - (NSString *)URLEncodedString; @end
#import "NSString+URL.h" @implementation NSString (URL) - (NSString *)URLEncodedString { NSString *encodedString = (NSString *) CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault, (CFStringRef)self, (CFStringRef)@"!$&‘()*+,-./:;=?@_~%#[]", NULL, kCFStringEncodingUTF8); return encodedString; } @end
调用方法:
NSString *encodedString = [urlString URLEncodedString];
//encodedString do something
原文：http://www.cnblogs.com/liuyingjie/p/5029684.html