Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    void deleteNode(ListNode* node) {
        //实际上只要将下一个节点的值覆盖当前节点，然后删除下一个节点就好了。注意这样不适用于尾节点
        node->val = node->next->val;
        node->next = node->next->next;
       
    }
};

Delete Node in a Linked List

原文：http://www.cnblogs.com/gofighting/p/5033176.html