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Valid Anagram

时间:2015-12-14 21:00:50      阅读:105      评论:0      收藏:0      [点我收藏+]
Total Accepted: 43676 Total Submissions: 111568 Difficulty: Easy

 

Given two strings s and t, write a function to determine if t is an anagram of s.

For example,
s = "anagram", t = "nagaram", return true.
s = "rat", t = "car", return false.

Note:
You may assume the string contains only lowercase alphabets.

Follow up:
What if the inputs contain unicode characters? How would you adapt your solution to such case?

 
class Solution {
public:
    bool isAnagram(string s, string t) {
        sort(s.begin(),s.end());
        sort(t.begin(),t.end());
        return s==t;
    }
};
Next challenges: (E) Palindrome Permutation

Valid Anagram

原文:http://www.cnblogs.com/zengzy/p/sort.html

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