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让人困惑的ThreadLocal

时间:2015-12-17 02:05:01      阅读:175      评论:0      收藏:0      [点我收藏+]

目前网上介绍ThreadLocal类用法的博文很多,看过后我们基本可以得出以下结论

ThreadLocal的作用和目的:
用于实现线程内的数据共享,即对于相同的程序代码,多个模块在同一个线程中运行时要共享一份数据,而在另外线程中运行时又共享另外一份数据。

好了,至此ThreadLocal的概念我们弄清了,它是每个线程的菊部变量(该死的输入法)。但是java有了类的局部变量,这个ThreadLocal是否显得多余,我们为什么或者在什么情况下用这个东西?

先看以下两段代码

?

代码1.使用ThreadLocal

?

public class ThreadLocalDemo implements Runnable {

	private final static ThreadLocal<Integer> tLocal = new ThreadLocal<Integer>();

	public static void main(String[] agrs) {
		ThreadLocalDemo td = new ThreadLocalDemo();
		Thread t1 = new Thread(td, "t1");
		Thread t2 = new Thread(td, "t2");
		t1.start();
		t2.start();
	}

	/**
	 * 示例业务方法
	 */
	public void test() {
		while (true) {
			try {
				Integer b = (Integer) tLocal.get();
				if (b == null) {
					b = 0;
					tLocal.set(b);
				}
				String currentThreadName = Thread.currentThread().getName();
				System.out.println("thread " + currentThreadName + " set value to:" + b++);
				tLocal.set(b);
				Thread.sleep(1000);
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}

	}

	@Override
	public void run() {
		test();
	}

}

运行结果:?

thread t2 set value to:0
thread t1 set value to:0
thread t1 set value to:1
thread t2 set value to:1
thread t1 set value to:2
thread t2 set value to:2
thread t1 set value to:3
thread t2 set value to:3

?

代码2.使用局部变量

?

public class ThreadLocalDemoMutli implements Runnable {

	private int a = 0;

	public static void main(String[] agrs) {
		ThreadLocalDemoMutli td = new ThreadLocalDemoMutli();
		ThreadLocalDemoMutli td2 = new ThreadLocalDemoMutli();
		Thread t1 = new Thread(td, "t1");
		Thread t2 = new Thread(td2, "t2");
		t1.start();
		t2.start();
	}

	/**
	 * 示例业务方法,用来测
	 */
	public void test() {
		while (true) {
			try {
				String currentThreadName = Thread.currentThread().getName();
				System.out.println("thread " + currentThreadName + " set age to:" + a++);
				Thread.sleep(1000);
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}

	}

	@Override
	public void run() {
		test();
	}
}

?运行结果

?

thread t1 set age to:0
thread t2 set age to:0
thread t1 set age to:1
thread t2 set age to:1
thread t2 set age to:2
thread t1 set age to:2
thread t1 set age to:3
thread t2 set age to:3

?

感觉用不用结果都一样嘛?再看下面代码

代码3

public class ThreadLocalDemoSingle implements Runnable {

	private int a = 0;

	public static void main(String[] agrs) {
		ThreadLocalDemoSingle td = new ThreadLocalDemoSingle();
		Thread t1 = new Thread(td, "t1");
		Thread t2 = new Thread(td, "t2");
		t1.start();
		t2.start();
	}

	/**
	 * 示例业务方法,用来测
	 */
	public void test() {
		while (true) {
			try {
				String currentThreadName = Thread.currentThread().getName();
				System.out.println("thread " + currentThreadName + " set age to:" + a++);
				Thread.sleep(1000);
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}

	}

	@Override
	public void run() {
		test();
	}
}

?运行结果:

thread t1 set age to:0
thread t2 set age to:1
thread t1 set age to:2
thread t2 set age to:3
thread t1 set age to:4
thread t2 set age to:5
thread t1 set age to:6
thread t2 set age to:7
thread t1 set age to:8
thread t2 set age to:9
thread t2 set age to:10
thread t1 set age to:11

?这回不一样了,对比代码2与代码3的区别就在于创建线程的时候

代码2里

ThreadLocalDemoMutli td = new ThreadLocalDemoMutli();
ThreadLocalDemoMutli td2 = new ThreadLocalDemoMutli();
		Thread t1 = new Thread(td, "t1");
		Thread t2 = new Thread(td2, "t2");

?代码3里

ThreadLocalDemoSingle td = new ThreadLocalDemoSingle();
		Thread t1 = new Thread(td, "t1");
		Thread t2 = new Thread(td, "t2");

?只不过多new了一个对象,原因也一眼看的清楚,但是始终没回答为什么要用ThreadLocal

?

?

?

看来只能从框架里找找原因了,下面搬出hibernate源码(我已经修改了很多)

代码4

public class HibernateUtil {

    //创建线程局部变量session,用来保存Hibernate的Session
    public static final ThreadLocal<Integer> session = new ThreadLocal<Integer>();
    
    public static Integer s2=0;
 
    /**
     * 获取当前线程中的Session
     * @return Session
     * @throws HibernateException
     */
    public static Integer currentSession()  {
        Integer s =   session.get();
        if (s == null) {
            s = 0;
            session.set(s);         
        }
        s++;
        session.set(s);         
        return s;
    }
    
    /**
     * 获取当前线程中的Session
     * @return Session
     * @throws HibernateException
     */
    public static Integer currentSessionError()  {
        return s2++;
    }
}

?

?

?代码5

public class THibernate implements Runnable {

	@Override
	public void run() {
		while (true) {
			try {
				String currentThreadName = Thread.currentThread().getName();
				System.out.println("thread " + currentThreadName +"|tlocal:"+HibernateUtil.currentSession()+"|common:"+HibernateUtil.currentSessionError());
				Thread.sleep(1000);
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
	}

	public static void main(String[] args) {
		THibernate t=new THibernate();
		Thread t1 = new Thread(t, "t1");
		Thread t2 = new Thread(t, "t2");
		t1.start();
		t2.start();
	}
}

?

?

?

?运行结果:

thread t1|tlocal:1|common:0
thread t2|tlocal:1|common:1
thread t1|tlocal:2|common:2
thread t2|tlocal:2|common:3
thread t1|tlocal:3|common:4
thread t2|tlocal:3|common:5
thread t1|tlocal:4|common:6
thread t2|tlocal:4|common:7
thread t1|tlocal:5|common:8
thread t2|tlocal:5|common:9

?HibernateUtil是一个可供多线程访问的工具类,从运行结果来看ThreadLocal做到了变量的线程隔离,而普通的类变量无法做到这点。

?那我把代码4里的

public static Integer s2=0;

?改成

public Integer s2=0;

?不就也完成了ThreadLocal做的事情吗

但是,你的方法是static的,用到的变量也需要是static的,在这种情况下,还真的必须用ThreadLocal,才能做到变量的线程隔离.

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?原创文章,转载请声名出处 ?http://spjich.iteye.com/blog/2264457

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让人困惑的ThreadLocal

原文:http://spjich.iteye.com/blog/2264457

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