You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip two consecutive "++" into "--". The game ends when a person can no longer make a move and therefore the other person will be the winner. Write a function to determine if the starting player can guarantee a win. For example, given s = "++++", return true. The starting player can guarantee a win by flipping the middle "++" to become "+--+". Follow up: Derive your algorithm‘s runtime complexity.
假设call这个function的人是先手, 然后尝试所有的翻转, 如果不能翻就说明先手的人不能保证必胜.
1 public class Solution { 2 public boolean canWin(String s) { 3 if (s==null || s.length()<=1) return false; 4 for (int i=0; i<s.length()-1; i++) { 5 if (s.charAt(i)==‘+‘ && s.charAt(i+1)==‘+‘ && !canWin(s.substring(0,i) + "--" + s.substring(i+2))) 6 return true; 7 } 8 return false; 9 } 10 }
原文:http://www.cnblogs.com/EdwardLiu/p/5081431.html